AP EAMCET Engineering 23 Apr 2019 Shift 1 Paper

Consider the projectile path of the body as shown below. If t is the time taken by projectile to cross the pole, then
30=(u‌cos‌45°)t
ut=30√2 …… (I)
And,
20=(u‌sin‌45°)t−

10

2

t2
20=30√2×

1

√2

−5t2
t=√2s
Now, from equation (I),
u√2=30√2
u=30m∕s
The range is calculated as,
R=

u2‌sin‌2‌θ

g

R=

(30)2‌sin(2×45°)

10

R=90m
The distance between pole and the point at which body strike on the ground is,
s=(90−30)m
s=60m