AP EAMCET Engineering 23 Apr 2019 Shift 1 Paper

Section: Mathematics

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Question : 73 of 160

Marks: +1, -0

∫ e2x [cos (3x + 4) + 5x2] dx =

e2x
[
2
13
cos(3x+4)+
3
13
sin(3x+4)+
5x2
2
−
5x
2
+
5
4
]
+ c
e2x
[
2
13
cos(3x+4)−
3
13
sin(3x+4)+
5x2
2
+
5x
2
+
5
4
]
+ c
e2x
[
2
13
cos(3x+4)+
3
13
sin(3x+4)+
5x2
2
−
5x
2
−
5
4
]
+ c
e2x
[
2
13
cos(3x+4)−
3
13
sin(3x+4)+
5x2
2
−
5x
2
+
5
4
]
+ c

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