AP EAMCET Engineering 23 Apr 2019 Shift 1 Paper

Consider the given points,
A=(1,2,3)
B=(3,−1,5)
C=(4,0,−3)
The direction of AB is (2,-3,2)
The direction of BC is (1,1,-8)
The direction of AC is (3,-2,-6)
It can be notices that AB⊥AC
So,∠A=90°
So, triangle is, The orthocenter of triangle ABC is vertex A so,
H=(1,2,3)
The circumcenter of ABC is equal to the mid point of BC so,
S=(

7

2

,

−1

2

,1)
Now, the required distance is,
(HS)=√

33

2