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Question : 32 of 160
Marks:
+1,
-0
Solution:
From the given data,
AP= and
AQ= Let,
D divide the line
AQ in ratio
λ:1 and
CP in
µ:1 then
= On comparison,
= and
= This implies,
= µ=6 So,
= 3λ+3=7λ λ= So,
AD= Then the area of triangle BCD is,
12|BC×BD|=|(b−a) ×()| =|(−5b×a)−(a×b)| =|a×b| It is given that area is 7 units so,
|a×b|= So, the area of triangle
ABC is
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