AP EAMCET Engineering 23 Apr 2019 Shift 1 Paper

By the method of verification if k = 0 ,
2.41+31=11t
8+3=11t
t=1
Now, from the second given relation on putting the values of (k,t)=(0,1), we get
2.(64)+81=11(p+39)
128+81=11(p+39)
11(p+39)=209
p+3q=19
From the option p must be 16 and q = 1 . So,
(3k+1)k=0