AP EAMCET Engineering 23 Apr 2019 Shift 1 Paper

The current in the circular loop is given by,
B=

µ0I

2R

I=

2BR

µ0

The magnetic moment of the loop is given by,
M=IA
M=

2BR

µ0

A ......(I)
The radius is given by,
A=πR2
R=√

A

π

...... (II)
From equation (I) and (II), we get
M=

2B√A∕π

µ0

A
M=

2BA√A

µ0√π