AP EAMCET Engineering 22 Sep 2020 Shift 1 Paper

It is given that roots of the equation x3−6x2+11x−6=0 are α,β,γ
Now, to find the equation whose roots are α2,β2,γ2, put α2=x⇒α=√x
Since, α is the root of the given equation, so x3∕2−6x+11x1∕2−6=0
⇒‌‌x1∕2(x+11)=6(x+1)
On squaring both sides, we get
x(x+11)2=36(x+1)2
⇒‌‌x[x2+22x+121]=36[x2+2x+1]
⇒‌‌x3+22x2+121x=36x2+72x+36
⇒‌‌x3−14x2+49x−36=0