AP EAMCET Engineering 22 Sep 2020 Shift 1 Paper

Equation of given lines
‌

x−1

1

=‌

y−2

2

=‌

z−5

−3

=r1( let ) ....(i)
and ‌

x+5

3

=‌

y−4

−1

=‌

z+3

4

=r2 (let)....(ii)
are intersecting lines, then on equating the parametric points on lines, we get
r1+1=3r2−5
2r1+2=−r2+4
and ‌‌−3r1+5=4r2+3
So on solving, r1=0 and r2=2
∴ Point of intersection is A(1,2,5).
Now the equation of planc parallel to xy-plane and passes through point A is z=5.