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Question : 100 of 160
Marks:
+1,
-0
Solution:
Given,
u=30+40ms−1 Force,
F=−(+5)‌N m‌‌=5kg uy‌‌=40ms−1,Fy=−5N ∴ Acceleration of body along
y-direction,
ay=‌=‌=−1ms−2 Using equation of straight line motion.
v=u+at vy=uy+at 0=40+(−1)t⇒t=40s
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