AP EAMCET Engineering 22 Sep 2020 Shift 1 Paper

Total number of ways to distribute five different books among four students randomly is 45=210=1024 and number of ways to distribute five different book among four students such that
‌

5!

1!1!1!2!3!

×4!=240
So, required probability is ‌

240

1024

=‌

24×3×5

210

=‌

15

64