If f (x) = \frac{(7x+1)sinx}{e^xlogx} and f' (x) = f (x) g (x) , then g' (x) =

Correct Answer is : 1x2logx + 1(xlogx)2 - cosec2 x - 49(7x+1)2

1/{x^2 \log x} + 1/(x \log x)^2 - cosec^2 x - {49}/(7x+1)^2

1/{x^2 \log x} + 1/(\log x) - cosec^2 x - {49}/(7x+1)^2

1/{(x^2 \log x)^2} + 1/( \log x) - cosec^2 x - {49}/(7x+1)^2

1/{x^2 \log x} + 1/(x \log x)^2 + cosec^2 x + {49}/(7x+1)^2

AP EAMCET Engineering 22 Apr 2019 Shift 2 Paper

Section: Mathematics

Question : 66 of 160

Marks: +1, -0

If f (x) =

(7x+1)sinx

exlogx

and f' (x) = f (x) g (x) , then g' (x) =

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