AP EAMCET Engineering 22 Apr 2019 Shift 1 Paper

The free body diagram of 2 kg block is shown below, The equilibrium equation for the block is,
f′=µR1
f′=(0.5)2g
f′=10N
since f′>2N, so 2‌kg block will move along the direction of 4kg body.
The net friction force on 2 kg block is,
f=f′−2
f=10−2
f=8N