© examsiri.com
Question : 77 of 160
Marks:
+1,
-0
Solution:
Let us consider,
I=dx ......(I)
Further simplify the above expression,
I=dx =dx =dx [∵bf(x)dx=f(a+b−x)dx] =dx =dx ....(II)
Add equation (I) and (II).
2I=dx+dx =
dx =cos‌x‌d‌x =[sin‌x]− Applying the limits, we get
2I=[1+1] =2 I=1 Now the value of given function is,
tan−1[dx]=tan−1(1) =tan−1(tan‌) =
© examsiri.com
Go to Question: