∫ {x.logx}/(\sqrt{x^2-1})^3 dx =

Correct Answer is : sec−1x−logx√x2−1 + c

\sec^{-1}x + {logx}/\sqrt{x^2-1} + c

\sec^{-1}x - {logx}/\sqrt{x^2-1} + c

{logx}/\sqrt{x^2-1} - \sec^{-1}x + c

- {logx}/\sqrt{x^2-1} - \sec^{-1}x + c

AP EAMCET Engineering 22 Apr 2019 Shift 1 Paper

Section: Mathematics

Question : 73 of 160

Marks: +1, -0

∫

x.logx

(√x2−1)3

dx =

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