AP EAMCET Engineering 22 Apr 2019 Shift 1 Paper

Consider the diagram,Let (a,b) be the coordinates of B.
From the diagram, it is clear that the midpoint of BQ is equal to the midpoint of PR so,
(

a−1

2

,

b−1

2

)=(

3+2

2

,

3+1

2

)
This implies,

a−1

2

=

5

2

a=5+1
=6
And,

b−2

2

=

4

2

b=4+2
=6
Thus, the coordinates of point B are (6,6) .
Now, the equation of BC can be obtained as,
y−6=

1−6

2−6

(x−6)
=

−5

−4

(x−6)
4y−24=5x−30
5x−4y=6