AP EAMCET Engineering 22 Apr 2019 Shift 1 Paper

Let us consider,

x+√3y

2

=

x+√3y

√1+(√3)2

=y
And,

√3x−y

2

=

√3x−y

√(√3)2+1

=x
So, the curve x+√3y2=(

√3x−y

2

)2 becomes y=x2.
Similarly, the curve

√3x−y

2

=(

x+√3y

2

)2 becomes x2=y.
Thus, the area of the region bounded by above curves is equal to the area bounded by the curves y=x2 and x=y2 which is equal to k .