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Question : 29 of 160
Marks:
+1,
-0
Solution:
Let us consider,
OA=(x−u)+x+x OB=x+(x−v)+x OC=x+x+(x−w) OD=(x−1)+(x−1) +(x−1) Here,
DA=(1−u)++ DB=+(1−v)+ DC=++(1−w) As the above points are collinear so,
[]=0 []=0 ++=1
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