AP EAMCET Engineering 22 Apr 2019 Shift 1 Paper

Gauss’s law states that,
ϕ E=

∮

s

EdA=

Q

∈0

Gauss’s law of magnetism states that the total magnetic flux passing through a bar magnet around its enclosed surface is zero.
ϕ B=

∮

s

BdA=0
According to Faraday’s law of electromagnetic induction,
ε=−

dϕB

dt

.....(I)
The electromotive force in a wire is the line integral, so
ε=∫Edl ....(II)
From equation (I) and (II),
∫Edl=−

dϕB

dt

In a time varying electric field, there exist an additionalcurrent to the conduction current known as displacement current. So, total current across the loop is,
i=ic+id
Here, ic is the conductor current and id is the displacement current.
Thus, the modified form of the Ampere’s law is,
∮Bdl=µ0i
∮Bdl=µ0[ic+id]
Thus, option (3) is correct.