Solve of the differential equation \frac{dy}{dx} = {1+y^2}/{(\Tan^{-1}y)-x}

Correct Answer is : xeTan−1y = eTan−1y((Tan−1y)−1)+c

xe^{\Tan^{-1}y} = e^{-\Tan^{-1}y}((\Tan^{-1}y)-1)+c

xe^{\Tan^{-1}y} = e^{\Tan^{-1}y}((\Tan^{-1}y)-1)+c

xe^{\Tan^{-1}y} = e^{\Tan^{-1}y}((\Tan^{-1}y)+1)+c

xe^{\Tan^{-1}y} = e^{-\Tan^{-1}y}((\Tan^{-1}y)+1)+c

AP EAMCET Engineering 21 Sep 2020 Shift 2 Paper

Section: Mathematics

Question : 78 of 160

Marks: +1, -0

Solve of the differential equation

1+y2

(Tan−1y)−x

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