Let ABCDEF be a regular hexagon with the vertices A, B, C, D, E, F counterclock-wise. Then the vector \overrightarrow{AB}+\overrightarrow{AF}+\overrightarrow{CD}+\overrightarrow{EF} is equal to

Correct Answer is : →BC+→DE

\overrightarrow{DE}+\overrightarrow{FA}

\overrightarrow{CB}+\overrightarrow{ED}

\overrightarrow{BC}+\overrightarrow{FA}

\overrightarrow{BC}+\overrightarrow{DE}

AP EAMCET Engineering 21 Sep 2020 Shift 2 Paper

Section: Mathematics

Question : 7 of 160

Marks: +1, -0

Let ABCDEF be a regular hexagon with the vertices A, B, C, D, E, F counterclock-wise. Then the vector

→

is equal to

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