If A = [\table3, 0, 0; 0, 5, 0; 0, 0, 4] and B = A^3, then B^{-1}=

Correct Answer is : [1270001125000164]

[\table {-3}, 0, 0; 0, {-5}, 0; 0, 0, {-4}]

[\table {-27}, 0, 0; 0, {-125}, 0; 0, 0, {-64}]

[\table {1/27}, 0, 0; 0, {1/125}, 0; 0, 0, {1/64}]

[\table {{-1}/27}, 0, 0; 0, {{-1}/125}, 0; 0, 0, {{-1}/64}]

AP EAMCET Engineering 21 Sep 2020 Shift 2 Paper

Section: Mathematics

Question : 57 of 160

Marks: +1, -0

If A = [

] and B = A3, then B−1=

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