If y = \sqrt{\frac{1+\tan x}{1-\tan x}}, then \frac{dy}{dx}=

Correct Answer is : 12(√1−tanx1+tanx)sec2(π4+x)

{1/2}(\sqrt{\frac{1-\tan x}{1+\tan x}})\sec^2({\pi/4}+x)

{1/2}(\sqrt{\frac{1-\tan x}{1+\tan x}})\sec({\pi/4}+x)

(\sqrt{\frac{1-\tan x}{1+\tan x}})\sec^2({\pi/4}+x)

{1/2}(\sqrt{\frac{1+\tan x}{1-\tan x}})\sec^2({\pi/4}+x)

AP EAMCET Engineering 21 Sep 2020 Shift 2 Paper

Section: Mathematics

Question : 27 of 160

Marks: +1, -0

If y = √

1+tan‌x

1−tan‌x

, then

Go to Question:

Prev Question

Next Question