AP EAMCET Engineering 21 Sep 2020 Shift 1 Paper

Let length of adjacent sides of rectangle is xcm and ycm so perimeter of rectangle is p=2(x+y)cm and the area A=xycm2
⇒‌‌A=x(‌

p

2

−x)
for maximaand y=‌

p

4

cm
∴ For given perimeter of rectangle p, the maximum possible area A=‌

p

4

×‌

p

4

=‌

p2

16

cm2