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Question : 18 of 160
Marks:
+1,
-0
Solution:
Given vector
a=2−3−4 b=+4−2 and
c=3−+4 and as we know that
[]=[]2 and
[a,b,c]=|| =2(16−2)+3(4+6)−4(−1−12)
=28+30+52=110 ∴[a×b‌‌b×c‌‌c×a]=[a,b,c]2=(110)2=12100
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