AP EAMCET Engineering 21 Sep 2020 Shift 1 Paper

Maximum force on the particle performing SHM,Fmax=10N
We know that, In SHM, when body is at maximum displacement (amplitude a ), then force on the particle is maximum.
∴‌‌Fmax=mass× acceleration =m⋅αmax
[∴αmax=ω2a]
⇒‌‌10=m⋅ω2a⇒10=maω2....(i)
Force on the particle when it is mid way (y=‌

a

2

) between mean and extreme position,
=‌

maω2

2

=‌

10

2

 [from Eq. (i)]
= 5 N