AP EAMCET Engineering 21 Sep 2020 Shift 1 Paper

According to question, the given situation is shown in the figure.Here, range, R=200+200=400m
Maximum height, H=100m
If θ be the direction of shot with respect to horizontal, then
R=‌

u2‌sin‌2‌θ

g

and H=‌

u2sin2θ

2g

∴‌‌‌

R

H

=‌

‌ u2‌sin‌2‌θ g

u2sin2θ 2g

⇒‌‌‌

400

100

=‌

2‌sin‌2‌θ

sin2θ

⇒‌‌1=tan‌θ
⇒‌‌tan‌45∘=tan‌θ
⇒‌‌45∘=θ
⇒‌‌θ=45∘