AP EAMCET Engineering 21 Apr 2019 Shift 2 Paper

It is given that the amplitude of the motion, A=2x0
The time required to distance from compressed position to
mean position is ‌

T

4

The displacement from mean position,
y=A‌sin‌ω‌t and
x0=2x0‌sin‌ω‌t
x0=2x0‌sin‌

2π

T

t
sin‌

π

6

=sin‌

2π

T

t
t=‌

T

12

Thus, the time taken to hit the wall,
‌

T

4

+‌

T

12

=‌

T

3

Or
The expression for the time period is,
T=2π√‌

m

k

So, the time taken to hit the wall is calculated as,
‌

T

3

=‌

2π

3

√‌

m

k