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Question : 79 of 160
Marks:
+1,
-0
Solution:
The differential equation is given as,
y=ex(a‌cos‌x+b‌sin‌x) Differentiate the above equation,
‌=ex(a‌cos‌x+b‌sin‌x)+ex(−a‌sin‌x+b‌cos‌x) ‌=y+ex(−a‌sin‌x+b‌cos‌x)‌‌‌‌‌⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅(I) Again differentiate the above equation,
‌=‌+ex(−a‌sin‌x+b‌cos‌x)+ex(−a‌cos‌x−b‌sin‌x) ‌=‌−ex(a‌cos‌x+b‌sin‌x)+‌−y ‌=2‌−y−ex(a‌cos‌x+b‌sin‌x) ‌=2‌−y−y ‌−2‌+2y=0
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