∫ x^2[\sqrt2 \sin (\pi/4+x)+e^x] dx =

Correct Answer is : (x2+2x−2) sin x + (−x2+2x+2) cos x + (x2−2x+2)ex + c

(x^2+2x-2) sin x + (-x^2 + 2x + 2) cos x + (x^2-2x+2)e^x + c

(-x^2+2x-2) sin x + (x^2 + 2x + 2) cos x + (x^2-2x+2)e^x + c

(x^2+2x+2) sin x + (-x^2 - 2x - 2) cos x + (x^2-2x+2)e^x + c

(x^2-2x-2) sin x + (-x^2 + 2x - 2) cos x + (x^2-2x+2)e^x + c

AP EAMCET Engineering 21 Apr 2019 Shift 2 Paper

Section: Mathematics

Question : 73 of 160

Marks: +1, -0

∫ x2[√2‌sin(

+x)+ex] dx =

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