AP EAMCET Engineering 21 Apr 2019 Shift 2 Paper

The equation of the parabola,
y2=4x
The equation of the normal to the parabola,
y2=4ax at (am2,−2am) is y=mx−2am−am3
Here, a=1, the equation of the normal becomes,
y=mx−2m−m3
since the normal is perpendicular to the line,
x+3y+1=0
Thus,
m1m2=−1
m(‌

−1

3

)=−1
m=3
Substitute the values in equation (I).
y=3x−2(3)−33
y=3x−6−27
3x−y=33