AP EAMCET Engineering 21 Apr 2019 Shift 2 Paper

The area of the circle is A=9π
The given equations are,
x+2y−5=0
2x−3y+4=0
From above equations, the value of x and y are 1 and 2 respectively.
The point of intersection is (x,y)=(1,2)
The area is,
πr2=9π
r2=9
The equation of the circle is,
(x−1)2+(y−2)2=9
x2+y2−2x−4y−4=0