AP EAMCET Engineering 21 Apr 2019 Shift 2 Paper

The equation of line given as, 4x+y−1=0,3x−4y+1=0
The slopes of line are, m1=−4 and m2=

3

4

Triangle ABC is an isosceles; AB=AC
AB and AC both passes through points (2,-7)
The slope is,
m3=|‌

−4− 3 4

1+(−4)(‌ 3 4 )

|=‌

19

8

The required equation of line AC is,
‌

y+7

x−2

=‌

‌ 3 4 − 19 8

1+‌ 3 4 ×‌ 19 8

After simplification,
89y+623=−52x+104
52x+89y+519=0