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Question : 33 of 160
Marks:
+1,
-0
Solution:
It is given that,
=2+− =+3 The cross product is,
×‌‌=|| ‌‌=(3−0)−(6+1)+(0−1) ‌‌=3−7− Therefore,
[]=U⋅(×) =|||×|cos‌θ =(1)(√9+49+1)‌cos‌θ =1(√59)‌cos‌θ The maximum value of
[] is
[]‌‌=(√59)‌cos‌0∘ ‌‌=√59
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