AP EAMCET Engineering 21 Apr 2019 Shift 2 Paper

The expression for moles of CHCl3 is given as,
n=‌

mCHCl3

MCHCl3

Here, the mass of CHCl3 is mCHCl3 and its molar mass is MCHCl3
Substitute the given value in above formula we get,
n=‌

59.75g

119.5g⋅mol−1

=0.5mol
The expression for moles of CH2Cl2 is given as,
n=‌

mCH2Cl2

MCH2Cl2

Here, the mass of CH2Cl2 is mCH2Cl2
and its molar mass is MCH2Cl2
Substitute the given value in above formula we get,
n=‌

21.25g

85g⋅mol−1

=0.25mol
The mole fraction of CH2Cl2 is given as:
χCH2Cl2=‌

nCH2Cl2

nCH2Cl2+nCHCl3

χCH2Cl2=‌

0.25

0.25+0.5

=0.33
The mole fraction of CHCl3 is given as
χCHCl3=1−χCH2Cl2
χCHCl3=1−0.33=0.67
The mole fraction of CHCl3 in vapour phase is given as,
yCHCl3=‌

pCHCl3

p10+(p20−p10)x2

yCHCl3=‌

134mm

200+(415−300)0.33

yCHCl3=0.494
The mole fraction of CH2Cl2 in vapour phase is given as
yCH2Cl2=‌

pCH2Cl2

p10+(p20−p10)x2

yCHCl3=‌

136.95mm

200+(415−300)0.33

yCHCl3=0.505