© examsiri.com
Question : 13 of 160
Marks:
+1,
-0
Solution:
It is given that,
≥ Rewrite the above equation.
(−)≥0 √6+x−x2()≥0 √6+x−x2()≥0 (x+1)(2x+5)(x+4)≤0 Now,
x∈(−∞,−4)∪[−,−1]⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅(I) For expression to be exist,
6+x−x2≥0 x2−x−6≤0 (x−3)(x+2)≤0 x∈[−2,3]⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅(II) From equation (I) and (II),
x∈[−2,−1]∪{3}
© examsiri.com
Go to Question: