AP EAMCET Engineering 21 Apr 2019 Shift 2 Paper

At the steady state, the capacitor behaves as open circuit. The figure below represents the simple circuit,
Apply Kirchhoff law in loop I,
−6+3(I1+I2)+2.8I1=0
5.8I1−3I2=6‌‌‌‌‌⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅(I)
Apply Kirchhoff law in loop II,
2I2+3(I2−I1)=0‌‌‌‌‌⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅(II)
From equation (I) and (II)
I2=0.9A
Thus, the current in 2Ω resistor is 0.9 A.