AP EAMCET Engineering 21 Apr 2019 Shift 2 Paper

The centripetal force is equal to the electrostatic force, when an electron revolves around a proton.
‌

mev2

r

=‌

kq1q2

r2

Rewrite the above equation.
mev2r=kq1q2
me(rω)2r=kqq
ω=√‌

kq2

mer3

Substitute the given values in the above equation.
ω=√‌

9×109×(1.6×10−19)2

9.1×10−31×(0.53×10−10)3

ω=4.1×1016s−1
The radial acceleration of electron can be calculated as,
ar=rω2
ar=0.53×10−10×(4.1×1016)2
ar=8.9×1022

m

s2

ar≈9×1022

m

s2