AP EAMCET Engineering 21 Apr 2019 Shift 1 Paper

The expression of the Newton's law of cooling is given by,
−‌

dT

dt

=k′(T−T0)
Integrate the equation on both sides.
∫‌

dT

T−T0

=k′‌∫dt
loge(T−T0)=−k′t
ln(T−T0)=−k′t
So,T=e−k′t+T0 for t→∞
And, T=T0 for T→∞
Hence, the temperature of the body varies exponentially with the
time from T to T0
Thus the graph of T verses t is shown below.