Two intervals of time are measured as Δ t_1 = (2.00 ± 0.02) s and Δ t_2 = (4.00 ± 0.02) s. The value of \sqrt{(\Deltat_1)(\Deltat_2)} with correct significant figures and error is

Correct Answer is : (2.83 ± 0.01) s

AP EAMCET Engineering 21 Apr 2019 Shift 1 Paper

Section: Physics

Question : 81 of 160

Marks: +1, -0

Two intervals of time are measured as Δ t1 = (2.00 ± 0.02) s and Δ t2 = (4.00 ± 0.02) s. The value of √(Δt1)(Δt2) with correct significant figures and error is

(2.828 ± 0.01) s
(2.83 ± 0.01) s
(2.828 ± 0.0075) s
(2.83 ± 0.0075) s

Validate

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