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Question : 61 of 160
Marks:
+1,
-0
Solution:
The given line is,
‌=‌=‌=λ So,(x,y,z)=(2λ+1,3λ−1,4λ+1) The above point is present on the given line so,
‌=‌=‌ Substitute values,
‌‌‌=‌=‌ ‌‌‌=‌ 2λ−2‌‌=4λ+1 λ‌‌=−‌ Now ‌‌‌=‌ ‌‌‌=‌ ‌‌‌=‌ k‌‌=‌
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