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Question : 31 of 160
Marks:
+1,
-0
Solution:
Consider the expression,
a+xb+yc=0 If
a+b+c=0 then
a×b=b×c=c×a≠0 If
a+xb+yc=0 Then,
(a×b)=xy(b×c)=y(c×a)=p So a×b=‌,b×c=‌,c×a=‌ Now
a×b−b×c+c×a‌‌=‌+‌+‌ ‌‌=p(‌) ‌‌=(‌)×xy×(b×c) ‌‌=(x+y+1)(b×c) Compare above with
6(b×c) then
x+y+1=6 x+y=5 x+y−5=0
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