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Question : 3 of 160
Marks:
+1,
-0
Solution:
Let
S=[12+(12+22)+(12+22+32)+......+(12+22+...+n2)] So
S‌‌=j2 ‌‌=‌ =‌[‌]2+‌[‌]+‌[‌] Simplify further.
S‌‌=‌‌+‌‌+‌‌ ‌‌=‌(n2+n+2n+2) ‌‌=‌[(n+1)(n+2)] ‌‌=‌
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