AP EAMCET Engineering 21 Apr 2019 Shift 1 Paper

Calculate the Normality of H2O2
‌ Normality of ‌H2O2‌‌=‌

‌ Volume strength ‌

‌ Equivalent weight ‌

‌‌=‌

20

5.6

‌‌=3.57N
The reaction is in acidic mediumfor KMnO4 so, valence factor will be 5 The normality of KMnO4 is,
NKMnO4=‌ Molarity ‌×5
Use the following expression.
N1V1(H2O2)=N2V2(KMnO4)
Substitute thevalues.
3.57×V1‌‌=0.02×5×500
V1‌‌=‌

50

3.57

‌‌=14.0mL