AP EAMCET Engineering 21 Apr 2019 Shift 1 Paper

Consider the below diagram.
The potential at the point A is calculated as,
VA‌‌=VA+q+VA−q
‌‌=‌

9×109×10−6

2×10−2

−‌

9×109×10−6

5×10−2

‌‌=9×105[‌

1

2

−‌

1

5

]
The potential at B is calculated as,
VB‌‌=VB+q+VB−q
‌‌=9×105[‌

1

5

−‌

1

2

]
The potential difference is calculated as
VA−VB=5.4×105V