If a and b are arbitrary constants, then the differential equation having x^2/a^2+y^2/b^2 = 1 as its general solution is

Correct Answer is : xy d2ydx2 + x (dydx)2 - y dydx = 0

(\frac{d^2y}{dx^2})^2 = [1+(\frac{dy}{dx})^2]^3

(x^2-y^2) \frac{d^2y}{dx^2} - 2xy \frac{dy}{dx} - y = 0

xy \frac{d^2y}{dx^2} + x (\frac{dy}{dx})^2 - y \frac{dy}{dx} = 0

x^2 \frac{d^2y}{dx^2} + 2x \frac{dy}{dx} - 2y = 0

AP EAMCET Engineering 2018 Apr 24 Shift 1 Paper

Section: Mathematics

Question : 79 of 160

Marks: +1, -0

If a and b are arbitrary constants, then the differential equation having

= 1 as its general solution is

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