Correct Answer is : x6 [(logx)36 - 112(logx)2+136logx - 1216] + c

x^6 [(logx)^3/{12} - 1/6 (logx)^2 + 1/6 \log x - 1/{36}] + c

x^6 [(logx)^3/{6} - 1/{18} (logx)^2 + 1/{12} \log x - 1/{36}] + c

x^6 [(logx)^3/{6} - 1/{12} (logx)^2 + 1/{12} \log x + 1/{36}] + c

x^6 [(logx)^3/{6} - 1/{12} (logx)^2 + 1/{36} \log x - 1/{216}] + c

AP EAMCET Engineering 2018 Apr 24 Shift 1 Paper

Section: Mathematics

Question : 75 of 160

Marks: +1, -0

∫ (logx)3x5 dx =

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