AP EAMCET Engineering 2018 Apr 24 Shift 1 Paper

Section: Mathematics

Question : 48 of 160

Marks: +1, -0

The equation of the pair of lines joining the origin to the points of intersection of two circles x2+y2 - 4x + 8y + 5 = 0 and x2+y2 + 2x + 4y - 3 = 0 is

13x2 + 6xy - 28y2 = 0
xy - 28y2 = 0
(x + 4) (x - 5) = 0
13x2 + 68xy - 28y2 = 0

Validate

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