The vertex A of a triangle lies on the lines x + y = 1 and 2x + 3y = 6. If the orthocentre of the triangle is O (3/7,{22}/7) , then the equation of OA in the normal form is

Correct Answer is : x cos α + y sin α = 13√17 ; α = tan−1(4)

x cos α + y sin α = 7 ; α = \tan^{-1} 1/7

x cos α + y sin α = {13}/\sqrt{17} ; α = \tan^{-1}(1/4)

x cos α + y sin α = {13}/4 α = \tan^{-1}({13}/\sqrt{17})

x cos α + y sin α = {13}/\sqrt{17} ; α = \tan^{-1}(4)

AP EAMCET Engineering 2018 Apr 24 Shift 1 Paper

Section: Mathematics

Question : 44 of 160

Marks: +1, -0

The vertex A of a triangle lies on the lines x + y = 1 and 2x + 3y = 6. If the orthocentre of the triangle is O (

) , then the equation of OA in the normal form is

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