Let S_n = \sum^{n}_{k=1} (-1)^{k-1}. k^2 for n ≥ 1. Given that S_{2n} = - n (2n + 1) for n = 1 , 2 , 3 , ... , then S_{77} =

AP EAMCET Engineering 2018 Apr 24 Shift 1 Paper

Section: Mathematics

Question : 3 of 160

Marks: +1, -0

Let Sn =

k=1

(−1)k−1.k2 for n ≥ 1. Given that S2n = - n (2n + 1) for n = 1 , 2 , 3 , ... , then S77 =

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