AP EAMCET Engineering 2018 Apr 24 Shift 1 Paper

The ratio of radii r1,r2,r3
r1:r2:r3=1:2:3
Let's assume
r1=x,r2=2x,r3=3x
s−a=

Δ

r1

=

Δ

x

s−b=

Δ

r1

=

Δ

2x

s−c=

Δ

r1

=

Δ

3x

Add the above three equations
3s−(a+b+c)=

Δ

x

+

Δ

2x

+

Δ

3x

s=

11Δ

6x

Therefore, the sides of the triangle is
a=

5Δ

6x

,b=

8Δ

6x

,c=

9Δ

6x

Therefore, the ratio of the sides of the triangle is
a:b:c=5:8:9